Matlab FOR Loop help!
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
_ I'm trying to get this function to work. But i keep getting an error. I am trying to determine the amount in the savings account for next 18 years, which is represented by x(k) in an array. Problem is that only the first value for the first month shows up in the array._ * _ * _
clc,clear
% Variable declaration
% x will be used to store the value of the new balance
% a will be used to store the value of the old balance
% i will be used to store the value of the interest rate
% c will be used to store the value of the user's contribution
% Variable initialization
a = input('Enter a value for the initial balance: ');
i = input('Enter a value for the interest rate: ');
c = input('Enter a value that you will contribute: ');
% Calculation
month = 1:12:216;
x=zeros(length(month));
for k=1:length(month);
x(k) = a + i(k) + c
end
10 commentaires
Sara
le 29 Juil 2014
Old balance is x(k-1) not a and I think interest means x(k-1)*i. The loop becomes:
x(1) = a;
for k = 2:numel(month)
x(k) = x(k-1)+ x(k-1)*i + c; %or x(k-1)*(i+1) + c;
end
If the interest is %, divide i by 100.
Réponses (1)
Ben11
le 29 Juil 2014
Modifié(e) : Ben11
le 30 Juil 2014
Maybe try this:
month = 1:12:216;
x=zeros(1,length(month)); % otherwise you have a 18*18 array
x(1) = a;
for k=2:length(month);
x(k) = x(k-1) + (i/100)*x(k-1) + c; % add the amount present during the previous month. Oh and I divided your interest rate by 100.
end
2 commentaires
Voir également
Catégories
En savoir plus sur Data Type Identification dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!