How to eliminate the repeated number?
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tabw
le 13 Août 2014
Réponse apportée : Geoff Hayes
le 13 Août 2014
For example,
number= 1: 10;
t=[1 3 5 7];
What I want to keep is [2 4 6 7 10];
how to do that?
assuming t and number have different dimensions.
In short, I want number array to have no same digits of t.
Thanks
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Azzi Abdelmalek
le 13 Août 2014
Modifié(e) : Azzi Abdelmalek
le 13 Août 2014
number= 1: 10;
t=[1 3 5 7];
out=setdiff(number,t)
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Geoff Hayes
le 13 Août 2014
tabw - consider using intersect. It will allow you to determine which values of t are in number, and then you can remove those common to both from number. Try the following
x = 1:10;
t = [1 3 5 7];
[common,indcsT,indcsX] = intersect(t,x)
% common is a vector of all values that are common to both t and x
% indcsT is a vector of indices into t of all common values
% indcsX is a vector of indices into x of all common values
% now remove the common elements from x
x(indcsX) = [];
The update x becomes
x =
2 4 6 8 9 10
It is slightly different from your example, but follows your instructions on wanting the first array to have no same digits as t.
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