How to extract a matrix of values from cell array of cell arrays of structs

8 vues (au cours des 30 derniers jours)
Jerry Guern
Jerry Guern le 28 Fév 2024
Commenté : Jerry Guern le 5 Mar 2024
I have an array of array of structs, and I'd like to extract the value 'metric' from each, into a simple matrix. cell2mat and other functions just gave me various errors, so I wrote the following give-up code. It works, but is there a better way?
msea = zeros(n1,n2);
for i=1:n1
for j=1:n2
msea(i,j)=mse{i}{j}.metric;
end
end
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Bruno Luong
Bruno Luong le 29 Fév 2024
Your data is not array of array of structs but cell array of cell array of structs. That's are not convenient to organize the data.
You might use for example 2D struct array if they have the same fields.
Jerry Guern
Jerry Guern le 29 Fév 2024
Modifié(e) : Jerry Guern le 4 Mar 2024
@Bruno Luong Yes, it would indeed be easier if the data came already in form the I wanted it. Unfortunately, there's a module that outputs whole populated structs that I can't change. And we can't know in advance how large the 2D output will be in either dimension. So I'm stuck with the form it arrives in. But I have edited my question to say "...cell array of cell arrays..." Thanks for the clarification.

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Bruno Luong
Bruno Luong le 1 Mar 2024
Ran in:
Generate data (Thanks Voss)
n1 = 3;
n2 = 4;
mse = cell(1,n1);
for ii = 1:n1
mse{ii} = cell(1,n2); % row vector
for jj = 1:n2
mse{ii}{jj} = struct('metric',ii+(jj-1)*n1);
end
end
Single line code
reshape([cell2mat(cat(1,mse{:})).metric],length(mse),[])
ans = 3×4
1 4 7 10 2 5 8 11 3 6 9 12
  2 commentaires
Bruno Luong
Bruno Luong le 1 Mar 2024
Déplacé(e) : Bruno Luong le 1 Mar 2024
I would first convert to struct array S
S = cell2mat(cat(1,mse{:}));
Then use S from now on and forget about mse.
metric_array = reshape([S.metric], size(S))
Jerry Guern
Jerry Guern le 5 Mar 2024
Thank you! I especially appreciate the way you gave me what I actually wanted AND a more practical solution that I should have wanted.

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Walter Roberson
Walter Roberson le 28 Fév 2024
Déplacé(e) : Walter Roberson le 28 Fév 2024
msea = zeros(n1,n2);
for i=1:n1
msea(i,1:n2) = [mse{i}{1:n2}.metric];
end
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Jerry Guern
Jerry Guern le 4 Mar 2024
@Stephen23 Thanks. I literally have no reason to avoid loops beyond appeasing the "coding standards" monitors. Vectorizing does also make for tidier code in other languages, but this is not always so for matlab, like this case for example.
Jerry Guern
Jerry Guern le 5 Mar 2024
If I wasn't required (against my wishes) to vectorize my code, I'd do is this way. This is succinct and highly readable code. The two best Answers I got on how fully vectorize this were respectively LONGER than this method and a single line of deep matlab code that I needed the manual to decipher. Left to my own devices THIS is how I'd code this up. Thanks.

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